5y^2+32y+35=0

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Solution for 5y^2+32y+35=0 equation: 


Simplifying
5y2 + 32y + 35 = 0

Reorder the terms:
35 + 32y + 5y2 = 0

Solving
35 + 32y + 5y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(5 + y)(7 + 5y) = 0


Subproblem 1
Set the factor '(5 + y)' equal to zero and attempt to solve:

Simplifying
5 + y = 0

Solving
5 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + y = 0 + -5
y = 0 + -5

Combine like terms: 0 + -5 = -5
y = -5

Simplifying
y = -5

Subproblem 2
Set the factor '(7 + 5y)' equal to zero and attempt to solve:

Simplifying
7 + 5y = 0

Solving
7 + 5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 5y = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 5y = 0 + -7
5y = 0 + -7

Combine like terms: 0 + -7 = -7
5y = -7

Divide each side by '5'.
y = -1.4

Simplifying
y = -1.4
Solution
y = {-5, -1.4}

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